SAT数学Problem Solving练习题(三)
http://en.jybest.cn 智课网 2016-05-19 大 中 小
特别提醒:科学填报志愿比取得好成绩更加重要。考试结束了,尽快估分选大学、确定志愿吧。请点击这里,帮你解决!
今天为大家准备了“SAT数学Problem Solving练习题(三)”, 供各位备考SAT的考生们参考使用,来提高自己的托福成绩!
Question #1: In the x,y plane, which of the following statements are true?
I. Line y + x = 5 is perpendicular to line y - x = 5.
II. Lines y + x = 5 and y - x = 5 intersect each other on the y axis.
III. Lines y + x = 5 and y - x = 5 intersect each other on the x axis.
(a) I and III are both true.
(b) I is the only true statement.
(c) II is the only true statement.
(d) I and II are both true.
Answer: y + x = 5 can be written as y = -x + 5. The slope of this equation is m1 = -1.
y - x = 5 can be written as y = x + 5. The slope of this equation is m2 = 1.
m2 = -1/m1 so the 2 lines are perpendicular.
We also need to find where the 2 lines intersect. If we add the 2 equations, 2·y = 10, y = 5.
From the first equation, x = 5 - y = 5 - 5 = 0. In conclusion the lines intersect at (0, 5) and this point is on the y axis.
In conclusion I and II statements are correct.
Question #2: If a is an integer chosen randomly from the set {3, 5, 6, 9} and b is an integer chosen randomly from the set {2, 3, 4}, what is the probability that a/b is an integer?
(a) .125
(b) .250
(c) .333
(d) .5
(e) .55
Answer: We have 4 possible integers for a and 3 for b, so the number of possible combinations for a/b is 4 · 3 = 12.
a/b is an integer only for 4 combinations:
1. a = 3 and b = 3
2. a = 6 and b = 2
3. a = 6 and b = 3
4. a = 9 and b = 3
The probability that a/b is an integer is 4/12 = 1/3 = .333.
Question #3: What is the value of integer a, if x = 2 is a solution of the equation √(a + x) = 2·x?
(a) a = 10
(b) a = 12
(c) a = 14
(d) a = 16
(e) a = 18
Answer: If we square the equation we get a + x = 4·x2
By replacing x with 2, a + 2 = 4·22, so a + 2 = 16.
In conclusion, a = 14.
Question #4: What is the value of (3x + 1 - 3x) / (3x - 3x - 1)?
(a) 6
(b) 3x
(c) 3x + 1
(d) 3x - 1
(e) 3
Answer: The numerator of the fraction is: 3x + 1 - 3x = 3x·(3 - 1) = 2 · 3x
The denominator of the fraction is: 3x - 3x - 1 = 3x - 1·(3 - 1) = 2 · 3x - 1
We can write the fraction as (2 · 3x) / (2 · 3x - 1) = 3x / 3x - 1 = 3
Question #5: Two diameters of a circle create an angle AOB of 45o between them. What is the length of arc AB if the radius of the circle is 10/¶?
(a) 5/2
(b) 3/2
(c) 2
(d) 4
(e) 6
Answer: The circumference of the circle is 2·¶·r = 2·¶·10/¶ = 20.
免责声明:
① 凡本站注明“稿件来源:中国教育在线”的所有文字、图片和音视频稿件,版权均属本网所有,任何媒体、网站或个人未经本网协议授权不得转载、链接、转贴或以其他方式复制发表。已经本站协议授权的媒体、网站,在下载使用时必须注明“稿件来源:中国教育在线”,违者本站将依法追究责任。
② 本站注明稿件来源为其他媒体的文/图等稿件均为转载稿,本站转载出于非商业性的教育和科研之目的,并不意味着赞同其观点或证实其内容的真实性。如转载稿涉及版权等问题,请作者在两周内速来电或来函联系。